10x^2+28x=6

Solution for 10x^2+28x=6 equation:

10x^2+28x=6

We move all terms to the left:

10x^2+28x-(6)=0

a = 10; b = 28; c = -6;
Δ = b2-4ac
Δ = 282-4·10·(-6)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-32}{2*10}=\frac{-60}{20}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+32}{2*10}=\frac{4}{20}
=1/5
$